2(1[3v-7]1)=16

Solution for 2(1[3v-7]1)=16 equation:

Simplifying
2(1[3v + -7] * 1) = 16

Reorder the terms:
2(1[-7 + 3v] * 1) = 16

Reorder the terms for easier multiplication:
2(1 * 1[-7 + 3v]) = 16

Multiply 1 * 1
2(1[-7 + 3v]) = 16
2([-7 * 1 + 3v * 1]) = 16
2([-7 + 3v]) = 16
(-7 * 2 + 3v * 2) = 16
(-14 + 6v) = 16

Solving
-14 + 6v = 16

Solving for variable 'v'.

Move all terms containing v to the left, all other terms to the right.

Add '14' to each side of the equation.
-14 + 14 + 6v = 16 + 14

Combine like terms: -14 + 14 = 0
0 + 6v = 16 + 14
6v = 16 + 14

Combine like terms: 16 + 14 = 30
6v = 30

Divide each side by '6'.
v = 5

Simplifying
v = 5